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华南理工大学:《物理化学》课程PPT教学课件(双语版)Chapter 2 热力学第一定律及其应用 The Thermodynamic First Law(下)

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2.1 Preface to the thermodynamics 2.2 The thermodynamic first law 2.3 Quasi-static process and reversible process 2.4 Enthalpy 2.5 Heat capacity 2.6 The first law in ideal gases 2.7 Thermochemistry 2.8 The Hess’s law 2.9 Heat in some processes 2.10 The temperature dependence of the reaction enthalpy —— Kirchhoff’s law 2.11 An adiabatic reaction ——non-isothermal reaction
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物理化学电子教案第二章(下) 热力学第一定律及其应用 环境 surroundings 无物质交换 封闭本系 closed system △U=Q+W 能量交换 4上一内容下一内容令回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 物理化学电子教案—第二章(下)  = + U Q W

Adiabatic process In Fig. PV T In reversible process the work A() done (below the line ab) is B/p: V,) big than the work done(below the line ac)in adiabatic Clp: v,) reversible process Slope in ab: 图1.6绝热可逆过程(AC)与 等温可逆过程(AB)功的图解(示意图) Slope in ac ap/=r y>1 4上一内容下一内容◇回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 Adiabatic process In Fig.PV: Slope in AB: ( )T p p V V  = −  Slope in AC: ( )S p p V V  = −  In reversible process the work done (below the line AB)is big than the work done (below the line AC) in adiabatic reversible process. 1   T

Fig. adiabatic and isothermal rev. process In an isothermal p expansion heat continuously flows B/: Vy) Into the system, and so the e pressure a C(p: V, does not fall as much as in a the normally isolated adiabatic F 图1.6绝热可逆过程(AC)与 expansion 等温可逆过程(AB)功的图解(示意图) 4上一内容下一内容令回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 Fig. adiabatic and isothermal rev. process In an isothermal expansion heat continuously flows into the system, and so the pressure does not fall as much as in a thermally isolated ,adiabatic expansion

Work in adiabatic process (1)work in pg. a. r. process 12 K y (P=K) K ecause P,v=p,V=K the erefore W=P22-P nR(T-T) 4上一内容下一内容令回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 Work in adiabatic process (1)work in pg. a. r. process. 2 1 = d V V K V V  −  1 1 2 1 = 1 1 ( ) (1 ) K V V    − − − − − therefore 2 2 1 1 = 1 p V pV W  − − p V p V K 1 1 2 2   because = = 2 1 d V V W p V = − ( ) pV K  = 2 1 ( ) 1 nR T T  − = −

a better calculation method (2)another way to calculate W=△U=2C1dT G(2-7)(设G与7无关) This equation is true for all adiabatic expansions or contractions involving a perfect gas or not, reversible or not 4上-内容下一内容◆回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 A better calculation method (2)another way to calculate W U =  This equation is true for all adiabatic expansions or contractions involving a perfect gas or not, reversible or not. 2 1 = ( ( ) C T T V C T V − 设 与 无关) 2 1 d T V T = C T 

2.7 real gas Joule- Thomson experiment Joule在1843年所做的气体自由膨胀实验是不够精 确的,1852年 Joule和 Thomson设计了新的实验,称为 throttling process 在这个实验中,使人们对实际气体的U和H的性质 有所了解,并且在获得低温和气体液化工业中有重要 应用。 4上一内容下一内容◇回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 2.7 real gas Joule-Thomson experiment Joule在1843年所做的气体自由膨胀实验是不够精 确的,1852年Joule和Thomson 设计了新的实验,称为 throttling process。 在这个实验中,使人们对实际气体的U和H的性质 有所了解,并且在获得低温和气体液化工业中有重要 应用

throttling process The Joule- Thomson expansion压缩区多膨胀区 consists of allowing a gas to expand through a porous plug P, V, T from a region of higher 焦耳一汤姆逊实验(1) pressure to a region of lower pressure as depicted in Fig 压缩区 多孔塞 膨胀区 pA The process is carried out steadily and adiabatically 焦耳一汤姆逊实验(2) 4上一内容下一内容◇回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 throttling process The Joule-Thomson expansion consists of allowing a gas to expand through a porous plug from a region of higher pressure to a region of lower pressure as depicted in Fig. The process is carried out steadily and adiabatically

throttling process 压缩区多孔塞膨胀区压缩区 多孔塞‖膨胀区 P 焦耳一汤姆逊实验(1) 焦耳一汤姆逊实验(2) When the flow is sufficiently slow, the gas has well defined pressure and temperature on both sides of the restriction 4上一内容下一内容令回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 throttling process When the flow is sufficiently slow,the gas has well defined pressure and temperature on both sides of the restriction

U and in the throttling process adiabatic 2 =0, then U7,-U1=△=W Left, Surroundings compresses gaseous system work, system got P1△=P1(△=0-1=-1) Right gaseous system expansion: work surr got 2=-P2△=-P2V2(△V=12-0=12) 4上一内容下一内容◆回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 U and H in the throttling process W p V 1 1 = −  Left, Surroundings compresses gaseous system: work, system got: Adiabatic Q=0 ,then: U U U W 2 1 − =  = Right, gaseous system expansion: work , surr. got: W p V 2 2 = −  1 1 1 1 =  − = − pV V V V ( =0 ) 2 2 2 2 = −  − = p V V V V ( = 0 )

U and in the throttling process the sum of work W=1+2=B1-P22 the en C2-1=n11-n2V2 C2+P2V2=C1+P1V1 、= 2 Throttling process is const -enthalpy process It is isenthalpic 4上一内容下一内容令回主目录 返回 2021/2/22

上一内容 下一内容 回主目录 返回 2021/2/22 U and H in the throttling process the sum of work: W W W pV p V = + = − 1 2 1 1 2 2 then U U pV p V 2 1 1 1 2 2 − = − Throttling process is const.-enthalpy process! H H 2 1 = U p V U pV 2 2 2 1 1 1 + = + It is isenthalpic

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