上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 36_Heat transfer and Work of internal reversible, ss flow

上游充通大学 SHANGHAI JIAO TONG UNIVERSITY Engineering Thermodynamics I Lecture 36 Chapter 7 Entropy (Section7.10-7.11) Spring,4/27/2018 漏 Prof.,Dr.Yonghua HUANG MMAMAA http://cc.sjtu.edu.cn/G2S/site/thermo.html
Engineering Thermodynamics I Lecture 36 Spring, 4/27/2018 Prof., Dr. Yonghua HUANG Chapter 7 Entropy (Section 7.10-7.11) http://cc.sjtu.edu.cn/G2S/site/thermo.html

Heat transfer in internally reversible,ss flow 1-intel,1-exit,ss CV,isothermal internally reversible y Entropy balance: +i6,-s)+。 T 0 =∫?Tds w=T(s-s) int rev m More generally ()= 上游究通大学 April 27,2018 2 SHANGHAI JLAO TONG UNIVERSITY
April 27, 2018 2 Heat transfer in internally reversible, ss flow 1-intel, 1-exit, ss CV, isothermal & internally reversible More generally Entropy balance:

Work in internal reversible,ss flow 1-intel,1-exit,ss CV,isothermal internally reversible ss,energy balance: -品价+)+ m Internally reversible! m 2nd entropy eq.Tds =dh-v dp T=-)- vdp =0 for nozzles/diffusers 0 下、(Bernoulli eq, ?-V3 J斤vdp +g(31-2) C W,in Chinese textbook (Often neglected) Technical work-the mechanical energy can be applied directly 上游充通大 April 27,2018 3 SHANGHAI JIAO TONG UNIVERSITY
April 27, 2018 3 Work in internal reversible, ss flow ss, energy balance: 1-intel, 1-exit, ss CV, isothermal & internally reversible Internally reversible 2 nd entropy eq. (Often neglected) Technical work- the mechanical energy can be applied directly Wt in Chinese textbook =0 for nozzles/diffusers (Bernoulli eq.)

Work in internal reversible,ss flow cont. If△PE,△KE are neglected: magnitude of v (Ake=△pe=0) Same Ap:pump (liquid),compressor (vapor),which work is larger? If v is const. Wey m int =-v(P2-p1) (v=constant,.△ke=△pe=O) rev Bernoulli equation 上游究通大学 April 27,2018 4 SHANGHAI JLAO TONG UNIVERSITY
April 27, 2018 4 Work in internal reversible, ss flow cont. Bernoulli equation If ∆PE, ∆KE are neglected: If v is const. : Same ∆p: pump (liquid), compressor (vapor), which work is larger? magnitude of v

Work in polytropic process,reversible,ss Polytropic:pu"constant If△PE,△KE are neglected: -=-omm -1 m rev pU2-p1U1) (polytropic,n≠l) Any gas/liquid Different from the one for closed system,eq.(3.54) w=P,',-D (n≠1) 1-n =-(p1w)ln(p2/p1) (polytropic,n 1) 上降文通大学 April 27,2018 5 SHANGHAI JIAO TONG UNIVERSITY
April 27, 2018 5 Work in polytropic process, reversible, ss Polytropic: If ∆PE, ∆KE are neglected: Any gas/liquid Different from the one for closed system, eq.(3.54) 2 2 1 1 ( n 1) 1 p v p v w n

Work in polytropic process,reversible,ss,Ideal gas Ideal gas:pv=RT M n m /int (polytropic,n≠1) rev nR int n-1 (T-T) (ideal gas,n≠I) rev (ideal gas,n≠1) =-(p心)lnp/p) int (polytropic,n 1) rev (ideal gas,n 1) m int =-RTIn(p2/p1) rev 上游充通大 April 27,2018 6 SHANGHAI JIAO TONG UNIVERSITY
April 27, 2018 6 Work in polytropic process, reversible, ss, Ideal gas Ideal gas: pv=RT or

Example 36.1 polytropic compression of air T2=425K 2 5bar Known:p1=1bar,T1=20C;p2=5bar n=1.3 pu3=constant Find: & -1 bar m m Shaded area=magnitude of (We)in rev Air compressor Assumptions: 1.SS,CV. 2.polytropic process,n =1.3. 3.air as an ideal gas. 4.△PE,△KE neglected 上游充通大学 April 27,2018 7 SHANGHAI JIAO TONG UNIVERSITY
April 27, 2018 7 Example 36.1 polytropic compression of air Known: p1 =1bar, T1=20℃; p2=5bar n=1.3 Find: & Assumptions: 1. SS, CV. 2. polytropic process, n = 1.3. 3. air as an ideal gas. 4. ∆PE, ∆KE neglected Air compressor

Solution Ideal gas,n=1.3≠1 nR 12 -T) (ideal gas,.n≠l) rev Polytropic process equation: (1.3-1)/1.3 T=T( =293 =425K Then, Wev nR 1.3 8.314kJ i 1.3-1 28.97kg·K (425-293)K=-164.2kJ/kg To find Q/m,use mass energy balance equation Ccv Wev -T1,T2,table A-17 m m h2-h =-164.15+(426.35-293.17))=-31kJ/kg 上游充通大 April 27,2018 8 SHANGHAI JIAO TONG UNIVERSITY
April 27, 2018 8 Solution Ideal gas, n=1.3 ≠ 1 ? Polytropic process equation: Then, To find Q/m, use mass & energy balance equation T1 , T2 , table A-17

Homework: Problems:M 6.155 上游充通大学 April 27,2018 9 SHANGHAI JLAO TONG UNIVERSITY
April 27, 2018 9 Homework: Problems: M_6.155
按次数下载不扣除下载券;
注册用户24小时内重复下载只扣除一次;
顺序:VIP每日次数-->可用次数-->下载券;
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 35_Isentropic processes, Isentropic efficiencies.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 34_Entropy balance to open systems.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 33_Entropy increase principle.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 32_Internally reversible processes, Closed system entropy balance.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 31_Retrieve entropy data.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 30_Clausius inequality and Entropy.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 29_Carnot Cycle.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 27-28_Applying 2nd law to thermodynamic cycles, Maximum performance.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 23-24_Introducing 2nd law, concept of irreversibilities.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 22_Transient analysis of Energy.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 20-21_Illustrations_3 Heat exchangers, throttling devices, System integration.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 19_Illustrations_2 Compressors, pumps.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 18_Illustrations_1 Nozzles, diffusers, turbines.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 17_Control volume analysis - energy conservation.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 16_Control volume analysis - mass conservation.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 15_Polytropic process.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 14_cv, cp, Δu, Δh of ideal gas and applied to close system.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 13_Equation of state and ideal gas model.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 12_Evaluating u, h, cp, cv properties.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 11_Retrieving pvt properties.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 37_Concept of exergy and apply to CM systems.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 38_Exergy of CV systems.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 39-40_vapor power cycles.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 41-42_superheat and reaheat.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 43-44_Vapor-compression refrigeration, Heat pump systems.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 45_Air standard cycle, internal combustion engines, Otto cycle.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 46_Diesel cycle and dual cycle.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 47_Compressor, compression with intercooling.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 48_Review and Final Exam.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 01-02_Course Introduction-web.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 03-04_Concepts.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 05-06_Energy, work, heat transfer.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 07-08_Energy balance for close system and cycles.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 09-10_Substance, property and phase.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 11_Retrieving pvt properties.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 12_Evaluating u, h, cp, cv properties.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 13_Equation of state and ideal gas model.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 14_cv, cp, Δu, Δh of ideal gas and applied to close system.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 15_Polytropic process.pdf
- 上海交通大学:《热力学 Thermodynamics(I)》课程教学资源(课件讲义)Lecture 16_Control volume analysis - mass conservation.pdf