《电力电子技术》课程教学课件（PPT讲稿）Topic 20 Converter based Power Factor Correction

Topic20Main contentsConverter based Power Factor Correction

Main contents • Converter based Power Factor Correction Topic 20

18-6-3 Interface for a Bidirectional power flow1 Thyristor Converters for 4-Quadrant OperationLd260-Hz?acinputCdUdFigure 18-7 Back-to-back connected converters forbidirectional powerflow.>The input current is has a distorted and the powerfactorislow

18-6-3 Interface for a Bidirectional power flow 1 Thyristor Converters for 4-Quadrant Operation ➢The input current is has a distorted and the power factor is low

2 Switch-Mode Converter Interface ☆（开关模式变流器、PWM变流器）DUdDonFigure18-8Switch-modeconverterfor the utility interface>

2 Switch-Mode Converter Interface ☆ (开关模式变流器、PWM变流器) Vd Vs ˆ

T1 1T3JD3eLD1A+VLVsV=CdVconvBOC2T4T2北FD.DoSingle-phasevoltage sourcePWM converter(1)各元件的作用☆单相电压型PWM变流器①支撑电容Cd：用于滤波，使直流侧电压恒定。②交流侧电感Ls：承担vs与Vcony之间的电压差，实现对输入电流相位的调节从而实现对功率因数的调节，同时也限制交流侧谐波电流diV. =V.+VLVIconvSdt

D1 D3 D2 D4 Single-phase voltage source PWM converter 单相电压型PWM变流器 T1 T3 T2 T4 is Ls vs A B L2 C2 Cd + - Vd + vL - vconv ① 支撑电容Cd：用于滤波，使直流侧电压恒定。 ② 交流侧电感Ls：承担vs与vconv之间的电压差，实现对 输入电流相位的调节从而实现对功率因数的调节，同时 也限制交流侧谐波电流。 (1) 各元件的作用☆ dt dis s conv L L s v = v + v v = L

+3TD3LDA+VLVd=CdconvOPS0Single-phasevoltagesourcePWMconverter单相电压型PWM变流器③二次滤波回路L2、C2：用于提供2次谐波电流通路，限制直流侧二次谐波电流，从而减小v中的二次谐波电压。其谐振频率为基波频率的2倍

③二次滤波回路L2、C2：用于提供2次谐波电流通路，限制直 流侧二次谐波电流，从而减小vd中的二次谐波电压。其谐振 频率为基波频率的2倍。 D1 D3 D2 D4 Single-phase voltage source PWM converter 单相电压型PWM变流器 T1 T3 T2 T4 is Ls vs A B L2 C2 Cd + - Vd + vL - vconv

(2) Analysis☆Assuming V, to be sinusoidal, at the line frequency w=2f,①ACsidePhasorequation（交流侧相量方程)：V=V+V=V+ joLI(18 -23)L1convlconvlslSSPhasordiagram(相量图)：Veonvi9=180°7Vt0=00vs161?1V.8LT(c)Veconvi(b)Figure 18-9 Rectification and inversion: (a) general phasor diagram; (b) rectificationat unitypowerfactor; (c)inversionatunitypowerfactor

(2) Analysis☆ (18 −23) s s1 + jL I  Assuming vs to be sinusoidal, at the line frequency ω=2πf, ① AC side Phasor equation (交流侧相量方程): V =V +V =V s conv1 L1 conv1 ② Phasor diagram (相量图):

3Theimportant equationsV2(comlsin)sconvlcoso)PVsVoLsoV-Vconvl(18 -26)sljoL,>For a given Vsand the chosen Ls, P and Q can beobtainedbycontrollingthemagnitudeandthephaseof Vconv1

③ The important equations: (18 −26) s s conv1 s1 Vs V V 2 V V 2 P = jL Q  s (1− conv1 cos ) Ls s ( conv1 sin ) Ls Vs = V −V I  ➢For a given vs and the chosen Ls , P and Q can be obtained by controlling the magnitude and the phase of vconv1

Inversion modeRectifier modeVeonvi6=0°la1V.★9=180°18VLIVLI8T下v.VconvcosO= -1cos= 1

Rectifier mode Inversion mode cos = 1 cos = −1

(3) Switch-Mode Converter ControlThere are various ways to implement the current loopcontrol:>Indirectcurrentcontrol（间接电流控制)>Directcurrentcontrol（直接电流控制）

(3) Switch-Mode Converter Control There are various ways to implement the current loop control: ➢Indirect current control (间接电流控制) ➢Direct current control (直接电流控制)

@ Indirect Current Control-----Base on phasor equationRectifier mode6=0°V.lg11v, = V, sin Ot8VlTVLi= OL,Is1VconviK, tanOL,VVconvlconvlcossin(ot -) →v.Vconv Sconvlconvl

① Indirect Current Control-Base on phasor equation: Rectifier mode ˆ ˆ conv1 conv1 conv1 conv1 conv1 s s Vˆ v =V = →Vˆ sin(t − ) → v s cos Is1 = s → Ls Vˆ vL1 = Ls Is1 Vˆ tan v =V sint