上海交通大学：《Design & Manufacturing II and Project》课程教学资源（作业）04_Bearing Solutions

ME357 Bearing Solutions 9-2 ANGULAR-CDUTACT OZSERIES BALL BEARING SELECTION 4D= SO000(4Bo)o 1ab s1440 RATIMG LIVEs.THE DESIGU LOAD 15 RADIAL,ANDIS Fp=1.4(6)=8541b =3.80 kN 三®.(9-6) 3 -85r["]'”25644s423kw TABLE 9-2:SELEcr 0z-SSmm wIrH C=46.2kN Ans. Us1J(Em.(9-18) a-exp(- =o.927As

ME357 Bearing Solutions 9-2 9 - 6 9 9 - 18

9-9 Inner ring rotate V=1,xp=270, a=0.5>e F First we find the bearing in 9-8 We calculate approximately first 270 C10=8× =51.8kW 11.438 0.02+4.439 In 0.9 TRIAL #1 Deep Groove 02-65mm C'10=55.9kN,Co=34kN Fe=10.2 kN C10=66.0kN TRIAL #2 02-75mmC'1o=66.3kN,Co=40.5kN ，。。， Fe=10.48kN C10=67.85kN TRIAL #3 02-80mmC'1o=70.2kN,C0=45kN Fe=10.6kN C10=68.51kN C'10>C10 Choose 02-80mm Deep Groove TRIAL #I Angular Contact 02-70mmC'1o=68.9kN,Co=45.5kN …… Fe=10.62kN C10=68.64kN C'10>C10 Choose 02-70mm Angular Contact

9-9 Inner ring rotate V=1, xD=270, e F F ra  0.5  First we find the bearing in 9-8 We calculate approximately first 1 3 10 1 1.438 270 8 51.8 1 0.02 4.439 ln 0.9 C kN                   TRIAL #1 Deep Groove 02-65mm C’10=55.9kN, C0=34kN …… Fe=10.2 kN C10=66.0 kN TRIAL #2 02-75mm C’10=66.3kN, C0=40.5kN …… Fe=10.48kN C10=67.85 kN TRIAL #3 02-80mm C’10=70.2kN, C0=45kN …… Fe=10.6kN C10=68.51kN C’10>C10 Choose 02-80mm Deep Groove√ TRIAL #1 Angular Contact 02-70 mm C’10=68.9kN, C0=45.5kN …… Fe=10.62kN C10=68.64kN C’10>C10 Choose 02-70mm Angular Contact√

73 So Cto=FD 270 =84.47kW 0.02+4.439 11.438 In- 0.96 For Deep Groove Choose 02-90mm C'10=95.6kN,Co=62kN Fe=11.12kN C1o0=88.81kN Choose 02-90mm Deep Groove For Angular contact Choose 02-85mm C'10=90.4kN,Co=63kN Fe=11.15kN C10=88.77kN Choose 02-85mm Angular Contact

So 1 3 10 1 1.438 270 84.47 1 0.02 4.439 ln 0.96 C FD kN                  For Deep Groove Choose 02-90mm C’10=95.6kN, C0=62kN Fe=11.12 kN C10=88.81kN Choose 02-90mm Deep Groove√ For Angular contact Choose 02-85mm C’10=90.4kN, C0=63kN Fe=11.15 kN C10=88.77kN Choose 02-85mm Angular Contact√

9-11 Sol Roll diameter D=4in Gear diameter D,=3in Roll load Ly =30lb/inx8in =240lb Idler Lz 24lb/inx8in=1921b Firstly,we do force analysis 水ROY 0 LY ROZ RAY LZ FZ FY Motion balance X-Axis M=M F2D,=LzD 1921b×4in F2= =2561b 3in F=Ftan20°=93.2lb Force system balance

9-11 Sol. Roll diameter D  4in Gear diameter 2 D  3in Roll load 30 / 8 240 LY  lb in in  lb 24 / 8 192 LZ  lb in in  lb Firstly, we do force analysis Motion balance X-Axis M  M Force system balance 2 192 4 256 3 tan 20 93.2 Z Z Z Y Y F D L D lb in F lb in F F lb       

个LY ROY RAY个 B A FY Y: Roy +Ray +Ly=Fy RAy×OA+Ly xOC=F×OB R4y=-4.51b Ror=-1421b 个L2 ROZ木 RAZ木 小FZ B 一X Z: Roz +Lz+Riz+F2=0 Lz×OC+R2×OA+F2×OB=0 R42=-413b Roz =-35lb R=VRz+Rm=V(-35)}+(-142)2=146b R4=√R2+R3y=V(-413)+(-4.51)2-413b Combined reliability is 0.92 Single reliability is 0.92 =0.96 30000×60×300 106 540

Y: Z: 0 0 OZ Z AZ Z Z AZ Z R L R F L OC R OA F OB           413 35 AZ OZ R lb R lb             2 2 2 2 2 2 2 2 35 142 146 413 4.51 413 O OZ OY A AZ AY R R R lb R R R lb               Combined reliability is 0.92 Single reliability is 0.92  0.96 OY AY Y Y AY Y Y R R L F R OA L OC F OB         4.51 142 AY OY R lb R lb     6 30000 60 300 540 10 Dx    

Using Weibull parameters and 1.2 application factor Shigley Page 454 3 540 C0=1.2×413× =22.15kWN 1.1483 0.02+4.439× 1 In- 0.96 Table 9-2 AC 02-35 can be selected 9-16 9-16.SHAFTS WITH A rHRUST CAM BE COUSTR NUED BEARIAS OE wHICN oUE SvPPoerS THE THEUST THE SHAFT FLOATS WITHIN THE EUAPLAy DE THE SECOND CROLLER) BEARUG.SILEE THE THAIT FRcE HERE IS LARGER THAN ANY RADIAL TRAL住21 LOAD,THe BEARUG A6S02AINg TEUTAnVELY SELECT D2-0SwM TH下H2v在TI在EAVILY LU49 ADCucht-courAcr Bdll wiTl COMPAR回ADn种OTHCA Go3131 k0.Co-BSkU BEARUG.THE SECOND BEAGUL IS OvGAS(飞E.1TDog5ur 5=- ·sD.029 COTRIBUTE ME ASURASLY TO THE LHANCE P FAILURE.THIS T4BLe9-【:Y2=9 IS PREDICTAALE.THE RELAAILIT =6.(o.s7力+t98(z,←7}=S42kN GOALIS MOT (0gg BuST o.39 。=3(542习=7.oskN FtH后B4LB后4他6.(0.0zC他./o4273 48El-:2=o,56,Y2=85 9形B之2在：R=1 2=o5L(e.9s7》+1.8s(2.47）=s1kN SPOTTINE FHIL EAAU Ave6 F。g4Fe=3C5o)=43kN REWORK=RDMo吗co.9oS 3 ANy⊙2-seA2 EA BEr比 910=6.b3( 17.493 a,o2+4439(me9) iLL Bo,S4M后BoRE oL =106.(k0 DT1 E DIAMETE2 rs A com制=小 CHaCE.CwNY?Aus

Using Weibull parameters and 1.2 application factor Shigley Page 454 Table 9-2 AC 02-35 can be selected 9-16 1 3 10 1 1.1483 540 1.2 413 22.15 1 0.02 4.439 ln 0.96 C kN                       9 - 16 9 9-18