《C++程序设计教程》教学资源（讲义）FORTRAN

SUBROUTINE NAMEAGE(NAME, NLEN, AGE, TEMP) CHARACTER*(*)NAME 工 NTEGER NLEN,AGE REAL TEMP WRITE(6, 1000) NAME(1: NLEN), AGE, TEMP 1000 FORMAT (IX, 'Hello,A,, who is, I2 ears old, has a temperature of RETURN END REAL A(5) COMMON/CC/X DATA A/1,2,3,4,5/ X=0 Y=FUN(A, 5)+FUN(A, 5) WRITE(*, *)Y END FUNCTION FUN (A,N REAL ACN) COMMON/CC/X X=X+1 END SUBROUTINE LAGINT (X,Y, N, T, Z) DIMENSIONX (N,Y(N) DOUBLE PRECISIONX,Y, T,X, S z=0.0 IF (N LEO)RETURN IF(NEQ。1)THEN (1) END工F IF(NEQ 2)THEN z=(Y(1)*〔TX(2))_Y(2)*〔TX(1)))/(X(1)-X(2))

SUBROUTINE NAMEAGE(NAME, NLEN, AGE, TEMP) CHARACTER*(*) NAME INTEGER NLEN,AGE REAL TEMP C WRITE(6,1000) NAME(1:NLEN),AGE,TEMP 1000 FORMAT(1X,'Hello ',A,', who is ',I2, . ' years old, has a temperature of ', f4.1) RETURN END C REAL A(5) COMMON /CC/X DATA A/1，2，3，4，5/ X=0 Y=FUN(A，5)+FUN(A，5) WRITE(*，*)Y END C FUNCTION FUN(A，N) REAL A(N) COMMON /CC/X X=X+1 F=1 END C SUBROUTINE LAGINT（X，Y，N ，T，Z） DIMENSION X（N），Y（N） DOUBLE PRECISION X，Y，T，X，S Z=0.0 IF (N.LE.0) RETURN IF(N.EQ.1) THEN Z=Y(1) ENDIF IF(N.EQ.2) THEN Z=(Y(1)*(T-X(2))-Y(2)*(T-X(1)))/(X(1)-X(2))

RETURN ENDIF 工=1 10 IF((I).LT. T) 工=T+1 IFCI LE. N GOTo 10 ENDIF K=工-4 IF(K LT. 1)K=1 M=I+3 IF( M.GT NM=N Do30工=K,M s=1.0 DO 20 J=K M IF(.NE. I)THEN S=s*〔T-X())/(X(I)-X() ENDIF 20 CONTINUE Z=Z+S*Y(I) 30 CONTINUE RETURN END

RETURN ENDIF I=1 10 IF(X(1) .LT. T) I=I+1 IF(I .LE. N) GOTO 10 ENDIF K=I-4 IF(K .LT. 1) K=1 M=I+3 IF( M .GT. N) M=N DO 30 I=K,M S=1.0 DO 20 J=K,M IF(J .NE. I) THEN S=S*(T-X(J))/(X(I)-X(J)) ENDIF 20 CONTINUE Z=Z+S*Y(I) 30 CONTINUE RETURN END